Jun 7, 2012

C Aptitude Questions and answers with explanation

C Aptitude 17
C program is one of most popular programming language which is used for core level of coding across the board. C program is used for operating systems, embedded systems, system engineering, word processors,hard ware drivers, etc.

In this site, we have discussed various type of C programs till date and from now on, we will move further by looking at the C aptitude questions.

In the coming days, we will post C aptitude questions, answers and explanation for interview preparations.

The C aptitude questions and answers for those questions along with explanation for the interview related queries.

We hope that this questions and answers series on C program will help students and freshers who are looking for a job, and also programmers who are looking to update their aptitude on C program.
Some of the illustrated examples will be from the various companies, and IT industry experts.
Read more about C Programming Language . and read the C Programming Language (2nd Edition). by K and R.
Predict the output or error(s) for the following:


C aptitude 17.1
  int i,j;
            for(i=0;i<=10;i++)
            {
            j+=5;
            assert(i<5);
            }


Answer: Runtime error: Abnormal program termination. assert failed (i<5), ,

Explanation: sserts are used during debugging to make sure that certain conditions are satisfied. If assertion fails, the program will terminate reporting the same. After debugging use, #undef NDEBUG and this will disable all the assertions from the source code. Assertion is a good debugging tool to make use of.

C aptitude 17.2
  main()
            {
            int i=-1;
            +i;
            printf("i = %d, +i = %d \n",i,+i);
            }

Answer: i = -1, +i = -1

Explanation:Unary + is the only dummy operator in C. Where-ever it comes you can just ignore it just because it has no effect in the expressions (hence the name dummy operator).


C aptitude 17.3
    main()
            {
            char *cptr,c;
            void *vptr,v;
            c=10;  v=0;
            cptr=&c; vptr=&v;
            printf("%c%v",c,v);
            }
Answer:Compiler error (at line number 4): size of v is Unknown.

Explanation: You can create a variable of type void * but not of type void, since void is an empty type. In the second line you are creating variable vptr of type void * and v of type void hence an error.

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