Oct 14, 2011

C Program to Demonstrate getting the parameters from the command line.

C Program to getting the parameters from the command line. To pass the arguments from command line, in main function we have to declare two arguments . First one is number of arguments passed to the program and other one is pointer variable which gives the list of arguments passed. Read more about C Programming Language .



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#include <stdio.h>

main(int argc, char *argv[]) {
 int count;

 /*  Main takes two variables 'argc' is the number of parms on the 
  *  command line and 'argv' is a pointer to each of the parameters.
  *
  * int argc    -- integer number called 'argc'
  * char *argv[] -- Character pointer array!
  */

 printf("%i parameters entered on the command line.\n", argc);

 /*
  * progname  argc = 1
  * progname parm1 parm2 argc = 3
  */

 /* 
  * We take 1 from argc because 
  * the argv array starts at zero 
  * an ends at argc -1
  */

 for (count = 0; count <= argc - 1; count++) {
  /* printf expects a pointer 
   * to the text 
   */

  printf("parm %d is %s\n", count, argv[count]);
 }
}
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